The registration for the exam started on 9 December 2024 and this is about the December edition of the exam.

Those who have submitted CSIR UGC NET December 2024 exam application, can take up corrections in their applications from 1 to 2  January 2025.

There will be five test papers in the exam and they are related to the subjects – Chemical Sciences, Earth, Atmospheric, Ocean and Planetary Sciences, Life Sciences, Mathematical Sciences and Physical Sciences.

What is CSIR UGC NET December 2024 Exam?

The full name of the exam is the Council of Scientific and Industrial Research University Grants Commission National Eligibility Test which is abbreviated as CSIR UGC NET.

It is a national-level exam conducted two times a year and is for candidates who wish to take up research (Junior Research Fellowship) in science subjects.

Those desiring to become assistant professors (job of lectureship) in science subjects can also apply.

The exam is conducted online and answers have to be registered on a computer screen at the designated test centers which will be located across India.

The questions are from the subjects – Chemical Sciences, Earth, Atmospheric, Ocean and Planetary Sciences, Life Sciences, Mathematical Sciences and Physical Sciences.

Format of the questions is multiple-choice where each question has more than one reply and the right one among that has to be chosen to get marks.

Who can submit CSIR UGC NET December 2024 Exam Application?

The eligibility to submit CSIR UGC NET December 2024 exam application is a pass in MSc or equivalent degree integrated BS-MS, BS-4years, BE, B.Tech, B.Pharma and MBBS.

Those desiring to submit CSIR UGC NET 2024 application must have a minimum pass marks or 55% in their qualifying exam if they are from General(UR)/General-EWS category applicants.

Same for OBC (NCL)/SC/ST category candidates is 50%. Candidates who have studied B.Sc. (Hons.) or equivalent or are enrolled in an integrated MS-PhD program can also take up CSIR UGC NET December 2024 exam application submission.

1. The URL mentioned above has to be typed into the browser and then submitted to allow the website to download.

2. Once the website is ready, candidates can read about the details of the exam.

3. After reading the details about the exam, they have to click the button Joint CSIR-UGC NET JUNE-2024: Click here to Registration/Login

4. Clicking the above button will open will open another webpage with URL ‘https://csirnetdec2024.ntaonline.in/’

5. Once the webpage with above URL opens, they can click the button New Candidate Register Here to register and open an account.

6. Post account creation, they can come to the URL ‘https://csirnetdec2024.ntaonline.in/’ and login using the credentials created during the registration and start filling CSIR UGC NET December 2024 exam application.

Direct Link to submit CSIR UGC NET December 2024 Exam Application is Here

How to download admit card?

The process to download admit card for the exam is online and candidates have to come to the official website of the exam to obtain it. The process to do that is mentioned below:

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1. The official website URL ‘https://csirnet.nta.ac.in/’ has to be typed into the browser and submitted to allow the website to download.

2. Once the website is ready, candidates have to click the link for admit card or hall ticket.

3. Clicking the link will open another webpage , once that opens, candidates have to type their application number and other details and submit them to view the admit card.

4. Once the admit card is visible, candidates have to download it and then take a print out of it.

The applicants must appear for the exam at the test center chosen by them. Those who pass the test with the required qualifying marks can apply for JRF or Assistant Professorship.

Individuals can access additional information from the official website which is mentioned above. They can visit the webpage periodically for updates.

The application submission started on 17 December 2024. The exam will be conducted on 23 March 2024.

Students have to pass GUJCET with required qualifying marks to be eligible for next phase of admission.

The answer key release and challenge and final result declaration are expected to take place in March 2025. The exact schedule will likely be made known at the appropriate time.

The test

GUJCET is also known as Gujarat Common Entrance Test (GUJCET) and is conducted by Gujarat Secondary and Higher Secondary Education Board (GSHSEB).

It is a state level exam conducted once every year and GUJCET 2025 is meant to be conducted for 2025.

The registration has opened and a notification is also released informing about the start of schedule for GUJCET 2025 registration.

Candidates keen on joining engineering or pharmacy courses at graduation in colleges across Gujarat can take up GUJCET 2025 registration. Details about GUJCET 2025 registration are available on the official website.

The subjects in plus-two must be maths, physics, and chemistry if applying for engineering through GUJCET 2025 registration.

Individuals focused on pharmacy must have biology, physics, and chemistry as subjects in plus-two.

Those willing to take up GUJCET 2025 registration must be passing their qualifying exam with 45% pass marks if they are from other categories.

Applicants from SC/ST/SEBC/EWS have to pass their qualifying exam with 40% pass marks.

How to take up GUJCET 2025 registration?

The process to apply for the test is online, candidates have to visit the official website with the help of the URL ‘https://gujcet.gseb.org/’ The procedure is mentioned below:

1. Candidates can type the earlier mentioned URL in the browsers of their computers and the webpage can be allowed to download.
2. Post-download, students have to click Click Here For New Candidate Registration
3. Clicking the above button will open webpage with URL ‘https://gujcet.gseb.org/’ showing the registration form.
4. Candidates must fill the form and create an account with username and password.
5. After creating an account, candidates can visit the website ‘https://gujcet.gseb.org/’
6. After the page is available, candidates can login with account credentials and start GUJCET 2025 registration.

Direct Link to take up GUJCET 2025 registration is here

Registration fee

The GUJCET 2025 registration fee has to be paid and the form can be submitted. Post submission, applicants have to wait for the message indicating successful submission. Once the message is obtained, candidates can download it and take a printout of it.

The fee is Rs 350 can be paid online through SBIePay system using Credit Card, Debit Card or Net Banking.

Fee can also be paid using ONLINE SBIePay “SBI Branch Payment” Option in any SBI Branch of the Country.

To pay inSBI Branch Log in to gujcet.gseb.org and in payment option SBIePay, Select SBI Branch payment option and take print out of payment slip.

Option for filling form will be shown only after successful payment. In case of failed payment status, application cannot be filled.

1. The URL mentioned above must be typed into the browser and submitted to allow the website to download.
2. Once the website is ready, candidates have to click the link for hall ticket.
3. Clicking the link for hall ticket will open another webpage.
4. When another webpage opens, they can enter the details like their application number and submit them to obtain admit card.
5. The hall ticket will be available likely on another webpage, once available candidates can download and take a printout.

Post application submission

Students who have completed GUJCET 2025 registration can wait for the hall ticket download which will be informed at the appropriate time on the official website.

The test will have questions related to 12th-standard maths/biology, physics, and chemistry lessons.

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GUJCET exam has to be passed with required cutoff marks or qualifying scores to become eligible to take part in the next process of admission which involves counseling or interview and document verification.